Base | Representation |
---|---|
bin | 10011011001100100001… |
… | …101011111011111010101 |
3 | 11201110000111120200122012 |
4 | 103121210031133133111 |
5 | 133320213001321323 |
6 | 2500232152114005 |
7 | 165212661361151 |
oct | 23314415373725 |
9 | 4643014520565 |
10 | 1333121120213 |
11 | 474412133013 |
12 | 19644b695905 |
13 | 98935ca081c |
14 | 48748328061 |
15 | 24a26a6a678 |
hex | 1366435f7d5 |
1333121120213 has 2 divisors, whose sum is σ = 1333121120214. Its totient is φ = 1333121120212.
The previous prime is 1333121120203. The next prime is 1333121120249. The reversal of 1333121120213 is 3120211213331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1128434549284 + 204686570929 = 1062278^2 + 452423^2 .
It is an emirp because it is prime and its reverse (3120211213331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1333121120213 - 220 = 1333120071637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1333121120203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666560560106 + 666560560107.
It is an arithmetic number, because the mean of its divisors is an integer number (666560560107).
Almost surely, 21333121120213 is an apocalyptic number.
It is an amenable number.
1333121120213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333121120213 is an equidigital number, since it uses as much as digits as its factorization.
1333121120213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1333121120213 its reverse (3120211213331), we get a palindrome (4453332333544).
The spelling of 1333121120213 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-one million, one hundred twenty thousand, two hundred thirteen".
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