13331231112001 has 4 divisors (see below), whose sum is σ = 14543161213104. Its totient is φ = 12119301010900.

The previous prime is 13331231111971. The next prime is 13331231112007. The reversal of 13331231112001 is 10021113213331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13331231112001 - 2¹³ = 13331231103809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331231112007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605965050535 + ... + 605965050556.

It is an arithmetic number, because the mean of its divisors is an integer number (3635790303276).

Almost surely, 2^{13331231112001} is an apocalyptic number.

13331231112001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13331231112001 is a deficient number, since it is larger than the sum of its proper divisors (1211930101103).

13331231112001 is a wasteful number, since it uses less digits than its factorization.

13331231112001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1211930101102.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13331231112001 its reverse (10021113213331), we get a palindrome (23352344325332).

The spelling of 13331231112001 in words is "thirteen trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred twelve thousand, one".