Base | Representation |
---|---|
bin | 10011011001100100010… |
… | …101000101110100001001 |
3 | 11201110000122022220010112 |
4 | 103121210111011310021 |
5 | 133320214004042301 |
6 | 2500232302524105 |
7 | 165213014325536 |
oct | 23314425056411 |
9 | 4643018286115 |
10 | 1333123112201 |
11 | 474413273691 |
12 | 196450296635 |
13 | 9893651a40a |
14 | 487486c5d8d |
15 | 24a26d109bb |
hex | 13664545d09 |
1333123112201 has 2 divisors, whose sum is σ = 1333123112202. Its totient is φ = 1333123112200.
The previous prime is 1333123112179. The next prime is 1333123112203. The reversal of 1333123112201 is 1022113213331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1286693205625 + 46429906576 = 1134325^2 + 215476^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1333123112201 is a prime.
Together with 1333123112203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1333123112203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666561556100 + 666561556101.
It is an arithmetic number, because the mean of its divisors is an integer number (666561556101).
Almost surely, 21333123112201 is an apocalyptic number.
It is an amenable number.
1333123112201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333123112201 is an equidigital number, since it uses as much as digits as its factorization.
1333123112201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1333123112201 its reverse (1022113213331), we get a palindrome (2355236325532).
The spelling of 1333123112201 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-three million, one hundred twelve thousand, two hundred one".
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