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13331311211441 is a prime number
BaseRepresentation
bin1100000111111111000000…
…0100011011001110110001
31202012110102222222220100102
43001333300010123032301
53221410011132231231
644204153025402145
72544104214416546
oct301776004331661
952173388886312
1013331311211441
11427a8606a5643
1215b3845199355
137591a2711172
1434134b7b0bcd
15181ba0b26acb
hexc1ff011b3b1

13331311211441 has 2 divisors, whose sum is σ = 13331311211442. Its totient is φ = 13331311211440.

The previous prime is 13331311211437. The next prime is 13331311211459. The reversal of 13331311211441 is 14411211313331.

It is a happy number.

13331311211441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12799250380816 + 532060830625 = 3577604^2 + 729425^2 .

It is a cyclic number.

It is not a de Polignac number, because 13331311211441 - 22 = 13331311211437 is a prime.

It is not a weakly prime, because it can be changed into another prime (13331311211641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665655605720 + 6665655605721.

It is an arithmetic number, because the mean of its divisors is an integer number (6665655605721).

Almost surely, 213331311211441 is an apocalyptic number.

It is an amenable number.

13331311211441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331311211441 is an equidigital number, since it uses as much as digits as its factorization.

13331311211441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 29.

Adding to 13331311211441 its reverse (14411211313331), we get a palindrome (27742522524772).

The spelling of 13331311211441 in words is "thirteen trillion, three hundred thirty-one billion, three hundred eleven million, two hundred eleven thousand, four hundred forty-one".