13331311211440 has 40 divisors (see below), whose sum is σ = 31431852080928. Its totient is φ = 5257418503680.

The previous prime is 13331311211437. The next prime is 13331311211441. The reversal of 13331311211440 is 4411211313331.

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 13331311211399 and 13331311211408.

It is not an unprimeable number, because it can be changed into a prime (13331311211441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1173525237 + ... + 1173536596.

Almost surely, 2^{13331311211440} is an apocalyptic number.

13331311211440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13331311211440 is an abundant number, since it is smaller than the sum of its proper divisors (18100540869488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13331311211440 is a wasteful number, since it uses less digits than its factorization.

13331311211440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2347061917 (or 2347061911 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 13331311211440 its reverse (4411211313331), we get a palindrome (17742522524771).

The spelling of 13331311211440 in words is "thirteen trillion, three hundred thirty-one billion, three hundred eleven million, two hundred eleven thousand, four hundred forty".