1333132002113 has 2 divisors, whose sum is σ = 1333132002114. Its totient is φ = 1333132002112.

The previous prime is 1333132002089. The next prime is 1333132002119. The reversal of 1333132002113 is 3112002313331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1332990320704 + 141681409 = 1154552^2 + 11903^2 .

It is an emirp because it is prime and its reverse (3112002313331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1333132002113 - 2⁶ = 1333132002049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1333132002119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666566001056 + 666566001057.

It is an arithmetic number, because the mean of its divisors is an integer number (666566001057).

Almost surely, 2^{1333132002113} is an apocalyptic number.

It is an amenable number.

1333132002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333132002113 is an equidigital number, since it uses as much as digits as its factorization.

1333132002113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1333132002113 its reverse (3112002313331), we get a palindrome (4445134315444).

The spelling of 1333132002113 in words is "one trillion, three hundred thirty-three billion, one hundred thirty-two million, two thousand, one hundred thirteen".