13331401121440 has 96 divisors (see below), whose sum is σ = 31546350170496. Its totient is φ = 5323947033600.

The previous prime is 13331401121359. The next prime is 13331401121443. The reversal of 13331401121440 is 4412110413331.

It is a junction number, because it is equal to n+sod(n) for n = 13331401121399 and 13331401121408.

It is not an unprimeable number, because it can be changed into a prime (13331401121443) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 251030890 + ... + 251083990.

It is an arithmetic number, because the mean of its divisors is an integer number (328607814276).

Almost surely, 2^{13331401121440} is an apocalyptic number.

13331401121440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13331401121440 is an abundant number, since it is smaller than the sum of its proper divisors (18214949049056).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13331401121440 is a wasteful number, since it uses less digits than its factorization.

13331401121440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55622 (or 55614 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13331401121440 its reverse (4412110413331), we get a palindrome (17743511534771).

The spelling of 13331401121440 in words is "thirteen trillion, three hundred thirty-one billion, four hundred one million, one hundred twenty-one thousand, four hundred forty".