Base | Representation |
---|---|
bin | 11110010011111110010111… |
… | …011001110000010000000111 |
3 | 122111000200210222011000102212 |
4 | 132103332113121300100013 |
5 | 114433204113140331044 |
6 | 1151311341522254035 |
7 | 40036422641053436 |
oct | 3623762731602007 |
9 | 574020728130385 |
10 | 133314030011399 |
11 | 395291874a7446 |
12 | 12b5119aab731b |
13 | 59505c77cca83 |
14 | 24cc60d68311d |
15 | 1062c0d05ba9e |
hex | 793f97670407 |
133314030011399 has 4 divisors (see below), whose sum is σ = 133983949760400. Its totient is φ = 132644110262400.
The previous prime is 133314030011347. The next prime is 133314030011483. The reversal of 133314030011399 is 993110030413331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133314030011399 - 28 = 133314030011143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133314630011399) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334959874202 + ... + 334959874599.
It is an arithmetic number, because the mean of its divisors is an integer number (33495987440100).
Almost surely, 2133314030011399 is an apocalyptic number.
133314030011399 is a deficient number, since it is larger than the sum of its proper divisors (669919749001).
133314030011399 is an equidigital number, since it uses as much as digits as its factorization.
133314030011399 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 669919749000.
The product of its (nonzero) digits is 78732, while the sum is 41.
The spelling of 133314030011399 in words is "one hundred thirty-three trillion, three hundred fourteen billion, thirty million, eleven thousand, three hundred ninety-nine".
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