Base | Representation |
---|---|
bin | 10011011001100101100… |
… | …010000111011110100111 |
3 | 11201110002001022202012202 |
4 | 103121211202013132213 |
5 | 133320234141212403 |
6 | 2500234303405115 |
7 | 165213351054212 |
oct | 23314542073647 |
9 | 4643061282182 |
10 | 1333143304103 |
11 | 474423705106 |
12 | 196456bb379b |
13 | 9893a769ca0 |
14 | 4874b260779 |
15 | 24a2899d688 |
hex | 136658877a7 |
1333143304103 has 32 divisors (see below), whose sum is σ = 1570581250560. Its totient is φ = 1119845191680.
The previous prime is 1333143304057. The next prime is 1333143304109. The reversal of 1333143304103 is 3014033413331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1333143304103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1333143304109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7648601 + ... + 7820957.
It is an arithmetic number, because the mean of its divisors is an integer number (49080664080).
Almost surely, 21333143304103 is an apocalyptic number.
1333143304103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1333143304103 is a deficient number, since it is larger than the sum of its proper divisors (237437946457).
1333143304103 is a wasteful number, since it uses less digits than its factorization.
1333143304103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173547.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 1333143304103 its reverse (3014033413331), we get a palindrome (4347176717434).
The spelling of 1333143304103 in words is "one trillion, three hundred thirty-three billion, one hundred forty-three million, three hundred four thousand, one hundred three".
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