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13332010093 is a prime number
BaseRepresentation
bin11000110101010011…
…00101010001101101
31021102010112021200121
430122221211101231
5204300443310333
610042531124541
7651244134043
oct143251452155
937363467617
1013332010093
115721632566
122700a43751
1313460c968c
149068b2393
1553068532d
hex31aa6546d

13332010093 has 2 divisors, whose sum is σ = 13332010094. Its totient is φ = 13332010092.

The previous prime is 13332010049. The next prime is 13332010103. The reversal of 13332010093 is 39001023331.

13332010093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13032962244 + 299047849 = 114162^2 + 17293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13332010093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13332010493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666005046 + 6666005047.

It is an arithmetic number, because the mean of its divisors is an integer number (6666005047).

Almost surely, 213332010093 is an apocalyptic number.

It is an amenable number.

13332010093 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332010093 is an equidigital number, since it uses as much as digits as its factorization.

13332010093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

The spelling of 13332010093 in words is "thirteen billion, three hundred thirty-two million, ten thousand, ninety-three".