Base | Representation |
---|---|
bin | 1100001000000001101001… |
… | …1100010000010011001101 |
3 | 1202012112021112122211202122 |
4 | 3002000122130100103031 |
5 | 3221412440124214242 |
6 | 44204351342302325 |
7 | 2544130636034462 |
oct | 302003234202315 |
9 | 52175245584678 |
10 | 13332022101197 |
11 | 4280095a02638 |
12 | 15b3a032879a5 |
13 | 759286a940a7 |
14 | 3413b7d81669 |
15 | 181be324aad2 |
hex | c201a7104cd |
13332022101197 has 2 divisors, whose sum is σ = 13332022101198. Its totient is φ = 13332022101196.
The previous prime is 13332022101191. The next prime is 13332022101227. The reversal of 13332022101197 is 79110122023331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12816765162601 + 515256938596 = 3580051^2 + 717814^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332022101197 - 26 = 13332022101133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13332022101191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666011050598 + 6666011050599.
It is an arithmetic number, because the mean of its divisors is an integer number (6666011050599).
Almost surely, 213332022101197 is an apocalyptic number.
It is an amenable number.
13332022101197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332022101197 is an equidigital number, since it uses as much as digits as its factorization.
13332022101197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 35.
The spelling of 13332022101197 in words is "thirteen trillion, three hundred thirty-two billion, twenty-two million, one hundred one thousand, one hundred ninety-seven".
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