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133320312121 is a prime number
BaseRepresentation
bin111110000101010000…
…0101000010100111001
3110202010022200120120211
41330022200220110321
54141014444441441
6141125124551121
712426541645423
oct1741240502471
9422108616524
10133320312121
11515a4927837
1221a088524a1
13c758a49369
14664a451813
1537045c9a81
hex1f0a828539

133320312121 has 2 divisors, whose sum is σ = 133320312122. Its totient is φ = 133320312120.

The previous prime is 133320312119. The next prime is 133320312131. The reversal of 133320312121 is 121213023331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114354890896 + 18965421225 = 338164^2 + 137715^2 .

It is a cyclic number.

It is not a de Polignac number, because 133320312121 - 21 = 133320312119 is a prime.

Together with 133320312119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 133320312092 and 133320312101.

It is not a weakly prime, because it can be changed into another prime (133320312131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660156060 + 66660156061.

It is an arithmetic number, because the mean of its divisors is an integer number (66660156061).

Almost surely, 2133320312121 is an apocalyptic number.

It is an amenable number.

133320312121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133320312121 is an equidigital number, since it uses as much as digits as its factorization.

133320312121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 133320312121 its reverse (121213023331), we get a palindrome (254533335452).

The spelling of 133320312121 in words is "one hundred thirty-three billion, three hundred twenty million, three hundred twelve thousand, one hundred twenty-one".