133320312131 has 2 divisors, whose sum is σ = 133320312132. Its totient is φ = 133320312130.

The previous prime is 133320312121. The next prime is 133320312133. The reversal of 133320312131 is 131213023331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133320312131 - 2¹⁴ = 133320295747 is a prime.

It is a super-2 number, since 2×133320312131² (a number of 23 digits) contains 22 as substring.

Together with 133320312133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133320312097 and 133320312106.

It is not a weakly prime, because it can be changed into another prime (133320312133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660156065 + 66660156066.

It is an arithmetic number, because the mean of its divisors is an integer number (66660156066).

Almost surely, 2^133320312131 is an apocalyptic number.

133320312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133320312131 is an equidigital number, since it uses as much as digits as its factorization.

133320312131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 133320312131 its reverse (131213023331), we get a palindrome (264533335462).

The spelling of 133320312131 in words is "one hundred thirty-three billion, three hundred twenty million, three hundred twelve thousand, one hundred thirty-one".