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13332102101159 is a prime number
BaseRepresentation
bin1100001000000001111100…
…1101011011100010100111
31202012112111010012021002012
43002000133031123202213
53221413121114214114
644204403321104435
72544132630030512
oct302003715334247
952175433167065
1013332102101159
114280127083806
1215b3a2602811b
1375929a52444a
143413c4847d79
15181bea29e63e
hexc201f35b8a7

13332102101159 has 2 divisors, whose sum is σ = 13332102101160. Its totient is φ = 13332102101158.

The previous prime is 13332102101089. The next prime is 13332102101161. The reversal of 13332102101159 is 95110120123331.

It is a strong prime.

It is an emirp because it is prime and its reverse (95110120123331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13332102101159 - 220 = 13332101052583 is a prime.

Together with 13332102101161, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13332102100159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666051050579 + 6666051050580.

It is an arithmetic number, because the mean of its divisors is an integer number (6666051050580).

Almost surely, 213332102101159 is an apocalyptic number.

13332102101159 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332102101159 is an equidigital number, since it uses as much as digits as its factorization.

13332102101159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 32.

The spelling of 13332102101159 in words is "thirteen trillion, three hundred thirty-two billion, one hundred two million, one hundred one thousand, one hundred fifty-nine".