1333211013131 has 4 divisors (see below), whose sum is σ = 1411635190392. Its totient is φ = 1254786835872.

The previous prime is 1333211013107. The next prime is 1333211013157. The reversal of 1333211013131 is 1313101123331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1333211013131 - 2¹⁸ = 1333210750987 is a prime.

It is a super-2 number, since 2×1333211013131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1333211013097 and 1333211013106.

It is not an unprimeable number, because it can be changed into a prime (1333211015131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39212088605 + ... + 39212088638.

It is an arithmetic number, because the mean of its divisors is an integer number (352908797598).

Almost surely, 2^{1333211013131} is an apocalyptic number.

1333211013131 is a deficient number, since it is larger than the sum of its proper divisors (78424177261).

1333211013131 is an equidigital number, since it uses as much as digits as its factorization.

1333211013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78424177260.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1333211013131 its reverse (1313101123331), we get a palindrome (2646312136462).

The spelling of 1333211013131 in words is "one trillion, three hundred thirty-three billion, two hundred eleven million, thirteen thousand, one hundred thirty-one".