133321121302133 has 4 divisors (see below), whose sum is σ = 133328375312640. Its totient is φ = 133313867291628.

The previous prime is 133321121302099. The next prime is 133321121302147. The reversal of 133321121302133 is 331203121123331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133321121302133 - 2¹⁴ = 133321121285749 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133321121302096 and 133321121302105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133321121305133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3626977685 + ... + 3627014442.

It is an arithmetic number, because the mean of its divisors is an integer number (33332093828160).

Almost surely, 2^{133321121302133} is an apocalyptic number.

It is an amenable number.

133321121302133 is a deficient number, since it is larger than the sum of its proper divisors (7254010507).

133321121302133 is an equidigital number, since it uses as much as digits as its factorization.

133321121302133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7254010506.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 133321121302133 its reverse (331203121123331), we get a palindrome (464524242425464).

The spelling of 133321121302133 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, one hundred twenty-one million, three hundred two thousand, one hundred thirty-three".