Base | Representation |
---|---|
bin | 1100001000000010101100… |
… | …0100001010110101000001 |
3 | 1202012112222222110100222222 |
4 | 3002000223010022311001 |
5 | 3221414023024000001 |
6 | 44204435144140425 |
7 | 2544140563450514 |
oct | 302005304126501 |
9 | 52175888410888 |
10 | 13332301000001 |
11 | 4280219384415 |
12 | 15b3a80767715 |
13 | 7592cc7b4479 |
14 | 341403020d7b |
15 | 181c0c98c61b |
hex | c202b10ad41 |
13332301000001 has 2 divisors, whose sum is σ = 13332301000002. Its totient is φ = 13332301000000.
The previous prime is 13332300999973. The next prime is 13332301000003. The reversal of 13332301000001 is 10000010323331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11462449869376 + 1869851130625 = 3385624^2 + 1367425^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332301000001 - 210 = 13332300998977 is a prime.
Together with 13332301000003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13332301000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666150500000 + 6666150500001.
It is an arithmetic number, because the mean of its divisors is an integer number (6666150500001).
Almost surely, 213332301000001 is an apocalyptic number.
It is an amenable number.
13332301000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332301000001 is an equidigital number, since it uses as much as digits as its factorization.
13332301000001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13332301000001 its reverse (10000010323331), we get a palindrome (23332311323332).
The spelling of 13332301000001 in words is "thirteen trillion, three hundred thirty-two billion, three hundred one million, one", and thus it is an aban number.
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