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133324888093 is a prime number
BaseRepresentation
bin111110000101011001…
…0000101100000011101
3110202010122022001122021
41330022302011200131
54141022132404333
6141125411020141
712426625564435
oct1741262054035
9422118261567
10133324888093
11515a7472831
1221a0a29a651
13c75998c137
14664acc32c5
153704bd082d
hex1f0ac8581d

133324888093 has 2 divisors, whose sum is σ = 133324888094. Its totient is φ = 133324888092.

The previous prime is 133324888079. The next prime is 133324888111. The reversal of 133324888093 is 390888423331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113125940964 + 20198947129 = 336342^2 + 142123^2 .

It is a cyclic number.

It is not a de Polignac number, because 133324888093 - 29 = 133324887581 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133324888093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133324888393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66662444046 + 66662444047.

It is an arithmetic number, because the mean of its divisors is an integer number (66662444047).

Almost surely, 2133324888093 is an apocalyptic number.

It is an amenable number.

133324888093 is a deficient number, since it is larger than the sum of its proper divisors (1).

133324888093 is an equidigital number, since it uses as much as digits as its factorization.

133324888093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2985984, while the sum is 52.

The spelling of 133324888093 in words is "one hundred thirty-three billion, three hundred twenty-four million, eight hundred eighty-eight thousand, ninety-three".