Base | Representation |
---|---|
bin | 111110000101100101… |
… | …0001100111111001111 |
3 | 110202011002012020221001 |
4 | 1330023022030333033 |
5 | 4141030242211231 |
6 | 141130154321131 |
7 | 12430033405264 |
oct | 1741312147717 |
9 | 422132166831 |
10 | 133331210191 |
11 | 515aaaa0703 |
12 | 21a104291a7 |
13 | c75b09391a |
14 | 664ba8b26b |
15 | 370552db61 |
hex | 1f0b28cfcf |
133331210191 has 2 divisors, whose sum is σ = 133331210192. Its totient is φ = 133331210190.
The previous prime is 133331210161. The next prime is 133331210219. The reversal of 133331210191 is 191012133331.
It is an a-pointer prime, because the next prime (133331210219) can be obtained adding 133331210191 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133331210191 - 213 = 133331201999 is a prime.
It is a super-2 number, since 2×1333312101912 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133331210161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66665605095 + 66665605096.
It is an arithmetic number, because the mean of its divisors is an integer number (66665605096).
Almost surely, 2133331210191 is an apocalyptic number.
133331210191 is a deficient number, since it is larger than the sum of its proper divisors (1).
133331210191 is an equidigital number, since it uses as much as digits as its factorization.
133331210191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 133331210191 in words is "one hundred thirty-three billion, three hundred thirty-one million, two hundred ten thousand, one hundred ninety-one".
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