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1333332042401 is a prime number
BaseRepresentation
bin10011011001110000110…
…010000110001010100001
311201110120012110122111002
4103121300302012022201
5133321131000324101
62500305125001345
7165221132235512
oct23316062061241
94643505418432
101333332042401
114745101a5a77
121964aa253255
139896a8b0358
1448768350a09
1524a3a330d6b
hex13670c862a1

1333332042401 has 2 divisors, whose sum is σ = 1333332042402. Its totient is φ = 1333332042400.

The previous prime is 1333332042377. The next prime is 1333332042403. The reversal of 1333332042401 is 1042402333331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1319686298176 + 13645744225 = 1148776^2 + 116815^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1333332042401 is a prime.

Together with 1333332042403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1333332042403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666666021200 + 666666021201.

It is an arithmetic number, because the mean of its divisors is an integer number (666666021201).

Almost surely, 21333332042401 is an apocalyptic number.

It is an amenable number.

1333332042401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333332042401 is an equidigital number, since it uses as much as digits as its factorization.

1333332042401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 1333332042401 its reverse (1042402333331), we get a palindrome (2375734375732).

The spelling of 1333332042401 in words is "one trillion, three hundred thirty-three billion, three hundred thirty-two million, forty-two thousand, four hundred one".