Base | Representation |
---|---|
bin | 11110010100010000011010… |
… | …000010000011000010110000 |
3 | 122111002112210222222122121110 |
4 | 132110100122002003002300 |
5 | 114434013301234401032 |
6 | 1151324304040153320 |
7 | 40041006661614360 |
oct | 3624203202030260 |
9 | 574075728878543 |
10 | 133333401481392 |
11 | 39536418161582 |
12 | 12b54aa6468840 |
13 | 5952393bccc58 |
14 | 24cd52a2b69a0 |
15 | 1063493a217cc |
hex | 79441a0830b0 |
133333401481392 has 80 divisors (see below), whose sum is σ = 394094796175872. Its totient is φ = 38052309050880.
The previous prime is 133333401481369. The next prime is 133333401481493. The reversal of 133333401481392 is 293184104333331.
It is a super-4 number, since 4×1333334014813924 (a number of 58 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (48).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 223391709 + ... + 223987772.
Almost surely, 2133333401481392 is an apocalyptic number.
133333401481392 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133333401481392 is an abundant number, since it is smaller than the sum of its proper divisors (260761394694480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133333401481392 is a wasteful number, since it uses less digits than its factorization.
133333401481392 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 447380386 (or 447380380 counting only the distinct ones).
The product of its (nonzero) digits is 1679616, while the sum is 48.
The spelling of 133333401481392 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, four hundred one million, four hundred eighty-one thousand, three hundred ninety-two".
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