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133343300164541 is a prime number
BaseRepresentation
bin11110010100011001101000…
…000010100001101110111101
3122111010111100212002212010212
4132110121220002201232331
5114434144034320231131
61151333022203242205
740041510166211045
oct3624315002415675
9574114325085125
10133343300164541
113953a637765755
1212b569a9519365
1359532b090540c
1424cdbc8bc4725
151063872a69a2b
hex7946680a1bbd

133343300164541 has 2 divisors, whose sum is σ = 133343300164542. Its totient is φ = 133343300164540.

The previous prime is 133343300164483. The next prime is 133343300164621. The reversal of 133343300164541 is 145461003343331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86067293344516 + 47276006820025 = 9277246^2 + 6875755^2 .

It is a cyclic number.

It is not a de Polignac number, because 133343300164541 - 210 = 133343300163517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133343300164141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66671650082270 + 66671650082271.

It is an arithmetic number, because the mean of its divisors is an integer number (66671650082271).

Almost surely, 2133343300164541 is an apocalyptic number.

It is an amenable number.

133343300164541 is a deficient number, since it is larger than the sum of its proper divisors (1).

133343300164541 is an equidigital number, since it uses as much as digits as its factorization.

133343300164541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 41.

The spelling of 133343300164541 in words is "one hundred thirty-three trillion, three hundred forty-three billion, three hundred million, one hundred sixty-four thousand, five hundred forty-one".