Base | Representation |
---|---|
bin | 111110000110110000… |
… | …1000000111001101111 |
3 | 110202020211120210201011 |
4 | 1330031201000321233 |
5 | 4141120402310211 |
6 | 141134125530051 |
7 | 12431023423411 |
oct | 1741541007157 |
9 | 422224523634 |
10 | 133370744431 |
11 | 51620343331 |
12 | 21a21713927 |
13 | c766326472 |
14 | 665301c9b1 |
15 | 3708c3c921 |
hex | 1f0d840e6f |
133370744431 has 2 divisors, whose sum is σ = 133370744432. Its totient is φ = 133370744430.
The previous prime is 133370744393. The next prime is 133370744471. The reversal of 133370744431 is 134447073331.
It is an a-pointer prime, because the next prime (133370744471) can be obtained adding 133370744431 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133370744431 is a prime.
It is a super-2 number, since 2×1333707444312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133370744471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66685372215 + 66685372216.
It is an arithmetic number, because the mean of its divisors is an integer number (66685372216).
Almost surely, 2133370744431 is an apocalyptic number.
133370744431 is a deficient number, since it is larger than the sum of its proper divisors (1).
133370744431 is an equidigital number, since it uses as much as digits as its factorization.
133370744431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 254016, while the sum is 40.
The spelling of 133370744431 in words is "one hundred thirty-three billion, three hundred seventy million, seven hundred forty-four thousand, four hundred thirty-one".
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