Base | Representation |
---|---|
bin | 11000110110010000… |
… | …00111010111001111 |
3 | 1021102200120221000202 |
4 | 30123020013113033 |
5 | 204310020422111 |
6 | 10043414444115 |
7 | 651402151121 |
oct | 143310072717 |
9 | 37380527022 |
10 | 13340014031 |
11 | 57260a9a93 |
12 | 270366363b |
13 | 134796c836 |
14 | 907997211 |
15 | 531216b3b |
hex | 31b2075cf |
13340014031 has 2 divisors, whose sum is σ = 13340014032. Its totient is φ = 13340014030.
The previous prime is 13340014013. The next prime is 13340014049. The reversal of 13340014031 is 13041004331.
Together with previous prime (13340014013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (13340014013) and next prime (13340014049).
It is a cyclic number.
It is not a de Polignac number, because 13340014031 - 214 = 13339997647 is a prime.
It is a super-2 number, since 2×133400140312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13340013994 and 13340014012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340014001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670007015 + 6670007016.
It is an arithmetic number, because the mean of its divisors is an integer number (6670007016).
Almost surely, 213340014031 is an apocalyptic number.
13340014031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340014031 is an equidigital number, since it uses as much as digits as its factorization.
13340014031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13340014031 its reverse (13041004331), we get a palindrome (26381018362).
The spelling of 13340014031 in words is "thirteen billion, three hundred forty million, fourteen thousand, thirty-one".
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