13340113 has 2 divisors, whose sum is σ = 13340114. Its totient is φ = 13340112.

The previous prime is 13340111. The next prime is 13340143. The reversal of 13340113 is 31104331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10705984 + 2634129 = 3272^2 + 1623^2 .

It is an emirp because it is prime and its reverse (31104331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13340113 - 2¹ = 13340111 is a prime.

It is a super-2 number, since 2×13340113² = 355917229705538, which contains 22 as substring.

Together with 13340111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13340111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670056 + 6670057.

It is an arithmetic number, because the mean of its divisors is an integer number (6670057).

Almost surely, 2^13340113 is an apocalyptic number.

It is an amenable number.

13340113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340113 is an equidigital number, since it uses as much as digits as its factorization.

13340113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 13340113 is about 3652.4119428126. The cubic root of 13340113 is about 237.1664044075.

Adding to 13340113 its reverse (31104331), we get a palindrome (44444444).

The spelling of 13340113 in words is "thirteen million, three hundred forty thousand, one hundred thirteen".