1334013004023 has 8 divisors (see below), whose sum is σ = 2032781720448. Its totient is φ = 762293145144.

The previous prime is 1334013004021. The next prime is 1334013004031. The reversal of 1334013004023 is 3204003104331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1334013004023 - 2¹ = 1334013004021 is a prime.

It is a super-2 number, since 2×1334013004023² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1334013003984 and 1334013004002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334013004021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31762214361 + ... + 31762214402.

It is an arithmetic number, because the mean of its divisors is an integer number (254097715056).

Almost surely, 2^{1334013004023} is an apocalyptic number.

1334013004023 is a deficient number, since it is larger than the sum of its proper divisors (698768716425).

1334013004023 is an equidigital number, since it uses as much as digits as its factorization.

1334013004023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63524428773.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 1334013004023 its reverse (3204003104331), we get a palindrome (4538016108354).

The spelling of 1334013004023 in words is "one trillion, three hundred thirty-four billion, thirteen million, four thousand, twenty-three".