13340132244431 has 2 divisors, whose sum is σ = 13340132244432. Its totient is φ = 13340132244430.

The previous prime is 13340132244401. The next prime is 13340132244433. The reversal of 13340132244431 is 13444223104331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13340132244431 - 2²⁶ = 13340065135567 is a prime.

It is a super-2 number, since 2×13340132244431² (a number of 27 digits) contains 22 as substring.

Together with 13340132244433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13340132244391 and 13340132244400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13340132244433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670066122215 + 6670066122216.

It is an arithmetic number, because the mean of its divisors is an integer number (6670066122216).

Almost surely, 2^{13340132244431} is an apocalyptic number.

13340132244431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340132244431 is an equidigital number, since it uses as much as digits as its factorization.

13340132244431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13340132244431 its reverse (13444223104331), we get a palindrome (26784355348762).

The spelling of 13340132244431 in words is "thirteen trillion, three hundred forty billion, one hundred thirty-two million, two hundred forty-four thousand, four hundred thirty-one".