Base | Representation |
---|---|
bin | 100111110000011… |
… | …0111000010110101 |
3 | 10102222011221100212 |
4 | 1033200313002311 |
5 | 10213001423013 |
6 | 340212315205 |
7 | 45025635014 |
oct | 11740670265 |
9 | 3388157325 |
10 | 1334014133 |
11 | 62501a621 |
12 | 312912b05 |
13 | 1834b709a |
14 | c9256a7b |
15 | 7c1ad6a8 |
hex | 4f8370b5 |
1334014133 has 2 divisors, whose sum is σ = 1334014134. Its totient is φ = 1334014132.
The previous prime is 1334014117. The next prime is 1334014139. The reversal of 1334014133 is 3314104331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1217870404 + 116143729 = 34898^2 + 10777^2 .
It is an emirp because it is prime and its reverse (3314104331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1334014133 - 24 = 1334014117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1334014099 and 1334014108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334014139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667007066 + 667007067.
It is an arithmetic number, because the mean of its divisors is an integer number (667007067).
Almost surely, 21334014133 is an apocalyptic number.
It is an amenable number.
1334014133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334014133 is an equidigital number, since it uses as much as digits as its factorization.
1334014133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
The square root of 1334014133 is about 36524.1582106967. The cubic root of 1334014133 is about 1100.8297136714.
Adding to 1334014133 its reverse (3314104331), we get a palindrome (4648118464).
The spelling of 1334014133 in words is "one billion, three hundred thirty-four million, fourteen thousand, one hundred thirty-three".
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