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1334022001103 = 11121274727373
BaseRepresentation
bin10011011010011001111…
…010000101000111001111
311201112100021202011220002
4103122121322011013033
5133324034113013403
62500501413114515
7165244210626101
oct23323172050717
94645307664802
101334022001103
11474834707180
12196661328a3b
1398a4a81513c
14487d1c33571
1524a7abbd188
hex13699e851cf

1334022001103 has 4 divisors (see below), whose sum is σ = 1455296728488. Its totient is φ = 1212747273720.

The previous prime is 1334022001093. The next prime is 1334022001141. The reversal of 1334022001103 is 3011002204331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1334022001103 - 28 = 1334022000847 is a prime.

It is a super-2 number, since 2×13340220011032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334022001163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60637363676 + ... + 60637363697.

It is an arithmetic number, because the mean of its divisors is an integer number (363824182122).

Almost surely, 21334022001103 is an apocalyptic number.

1334022001103 is a deficient number, since it is larger than the sum of its proper divisors (121274727385).

1334022001103 is a wasteful number, since it uses less digits than its factorization.

1334022001103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121274727384.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1334022001103 its reverse (3011002204331), we get a palindrome (4345024205434).

The spelling of 1334022001103 in words is "one trillion, three hundred thirty-four billion, twenty-two million, one thousand, one hundred three".

Divisors: 1 11 121274727373 1334022001103