133404000000 has 252 divisors, whose sum is σ = 443845724952. Its totient is φ = 35571200000.

The previous prime is 133403999987. The next prime is 133404000007. The reversal of 133404000000 is 404331.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133404000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 11994442 + ... + 12005558.

Almost surely, 2^133404000000 is an apocalyptic number.

133404000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133404000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221922862476).

133404000000 is an abundant number, since it is smaller than the sum of its proper divisors (310441724952).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133404000000 is an frugal number, since it uses more digits than its factorization.

133404000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11166 (or 11127 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 133404000000 its reverse (404331), we get a palindrome (133404404331).

The spelling of 133404000000 in words is "one hundred thirty-three billion, four hundred four million", and thus it is an aban number.