Base | Representation |
---|---|
bin | 11000110110010011… |
… | …01000010100000111 |
3 | 1021102201100002202121 |
4 | 30123021220110013 |
5 | 204310121124033 |
6 | 10043431150411 |
7 | 651405423643 |
oct | 143311502407 |
9 | 37381302677 |
10 | 13340411143 |
11 | 5726350384 |
12 | 2703815407 |
13 | 1347a7b507 |
14 | 907a5bc23 |
15 | 53129462d |
hex | 31b268507 |
13340411143 has 2 divisors, whose sum is σ = 13340411144. Its totient is φ = 13340411142.
The previous prime is 13340411111. The next prime is 13340411153. The reversal of 13340411143 is 34111404331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13340411143 - 25 = 13340411111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340411153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670205571 + 6670205572.
It is an arithmetic number, because the mean of its divisors is an integer number (6670205572).
Almost surely, 213340411143 is an apocalyptic number.
13340411143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340411143 is an equidigital number, since it uses as much as digits as its factorization.
13340411143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13340411143 its reverse (34111404331), we get a palindrome (47451815474).
The spelling of 13340411143 in words is "thirteen billion, three hundred forty million, four hundred eleven thousand, one hundred forty-three".
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