Base | Representation |
---|---|
bin | 11000110110010011… |
… | …01010011110110001 |
3 | 1021102201100112221021 |
4 | 30123021222132301 |
5 | 204310121420032 |
6 | 10043431255441 |
7 | 651405461551 |
oct | 143311523661 |
9 | 37381315837 |
10 | 13340420017 |
11 | 5726357011 |
12 | 270381a581 |
13 | 1347a82572 |
14 | 907a61161 |
15 | 531297097 |
hex | 31b26a7b1 |
13340420017 has 2 divisors, whose sum is σ = 13340420018. Its totient is φ = 13340420016.
The previous prime is 13340419943. The next prime is 13340420029. The reversal of 13340420017 is 71002404331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12648151296 + 692268721 = 112464^2 + 26311^2 .
It is a cyclic number.
It is not a de Polignac number, because 13340420017 - 231 = 11192936369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13340419973 and 13340420000.
It is not a weakly prime, because it can be changed into another prime (13340420077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670210008 + 6670210009.
It is an arithmetic number, because the mean of its divisors is an integer number (6670210009).
Almost surely, 213340420017 is an apocalyptic number.
It is an amenable number.
13340420017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340420017 is an equidigital number, since it uses as much as digits as its factorization.
13340420017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 13340420017 its reverse (71002404331), we get a palindrome (84342824348).
The spelling of 13340420017 in words is "thirteen billion, three hundred forty million, four hundred twenty thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •