Base | Representation |
---|---|
bin | 11000110110010011… |
… | …01010011101100111 |
3 | 1021102201100112211112 |
4 | 30123021222131213 |
5 | 204310121414233 |
6 | 10043431255235 |
7 | 651405461414 |
oct | 143311523547 |
9 | 37381315745 |
10 | 13340419943 |
11 | 5726356a54 |
12 | 270381a51b |
13 | 1347a82516 |
14 | 907a6110b |
15 | 531297048 |
hex | 31b26a767 |
13340419943 has 2 divisors, whose sum is σ = 13340419944. Its totient is φ = 13340419942.
The previous prime is 13340419903. The next prime is 13340420017. The reversal of 13340419943 is 34991404331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13340419943 - 26 = 13340419879 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13340419943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340419903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670209971 + 6670209972.
It is an arithmetic number, because the mean of its divisors is an integer number (6670209972).
Almost surely, 213340419943 is an apocalyptic number.
13340419943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340419943 is an equidigital number, since it uses as much as digits as its factorization.
13340419943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 13340419943 in words is "thirteen billion, three hundred forty million, four hundred nineteen thousand, nine hundred forty-three".
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