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13340431121 is a prime number
BaseRepresentation
bin11000110110010011…
…01101001100010001
31021102201101010011112
430123021231030101
5204310122243441
610043431423105
7651405536123
oct143311551421
937381333145
1013340431121
115726364396
122703824a95
131347a87634
14907a65213
1553129a4eb
hex31b26d311

13340431121 has 2 divisors, whose sum is σ = 13340431122. Its totient is φ = 13340431120.

The previous prime is 13340431109. The next prime is 13340431123. The reversal of 13340431121 is 12113404331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8775942400 + 4564488721 = 93680^2 + 67561^2 .

It is a cyclic number.

It is not a de Polignac number, because 13340431121 - 222 = 13336236817 is a prime.

Together with 13340431123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13340431123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670215560 + 6670215561.

It is an arithmetic number, because the mean of its divisors is an integer number (6670215561).

Almost surely, 213340431121 is an apocalyptic number.

It is an amenable number.

13340431121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340431121 is an equidigital number, since it uses as much as digits as its factorization.

13340431121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13340431121 its reverse (12113404331), we get a palindrome (25453835452).

The spelling of 13340431121 in words is "thirteen billion, three hundred forty million, four hundred thirty-one thousand, one hundred twenty-one".