Base | Representation |
---|---|
bin | 11000110110010100… |
… | …01010001111010111 |
3 | 1021102201121011101021 |
4 | 30123022022033113 |
5 | 204310140100403 |
6 | 10043434142011 |
7 | 651406543036 |
oct | 143312121727 |
9 | 37381534337 |
10 | 13340550103 |
11 | 5726435821 |
12 | 2703881907 |
13 | 1347ac983a |
14 | 907a9671d |
15 | 5312c08bd |
hex | 31b28a3d7 |
13340550103 has 2 divisors, whose sum is σ = 13340550104. Its totient is φ = 13340550102.
The previous prime is 13340550089. The next prime is 13340550107. The reversal of 13340550103 is 30105504331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13340550103 - 225 = 13306995671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340550107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670275051 + 6670275052.
It is an arithmetic number, because the mean of its divisors is an integer number (6670275052).
Almost surely, 213340550103 is an apocalyptic number.
13340550103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340550103 is an equidigital number, since it uses as much as digits as its factorization.
13340550103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 25.
It can be divided in two parts, 13 and 340550103, that added together give a square (340550116 = 184542).
The spelling of 13340550103 in words is "thirteen billion, three hundred forty million, five hundred fifty thousand, one hundred three".
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