Base | Representation |
---|---|
bin | 11000110110011000… |
… | …10001001110111011 |
3 | 1021102202122020212020 |
4 | 30123030101032323 |
5 | 204310310244120 |
6 | 10043454045523 |
7 | 651414335061 |
oct | 143314211673 |
9 | 37382566766 |
10 | 13341103035 |
11 | 5726783197 |
12 | 2703aa98a3 |
13 | 1347c61410 |
14 | 907b9c031 |
15 | 53137e640 |
hex | 31b3113bb |
13341103035 has 32 divisors (see below), whose sum is σ = 23069648448. Its totient is φ = 6544527360.
The previous prime is 13341103031. The next prime is 13341103043. The reversal of 13341103035 is 53030114331.
It is not a de Polignac number, because 13341103035 - 22 = 13341103031 is a prime.
It is a super-2 number, since 2×133411030352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13341102996 and 13341103014.
It is not an unprimeable number, because it can be changed into a prime (13341103031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66942 + ... + 176531.
It is an arithmetic number, because the mean of its divisors is an integer number (720926514).
Almost surely, 213341103035 is an apocalyptic number.
13341103035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13341103035 is a deficient number, since it is larger than the sum of its proper divisors (9728545413).
13341103035 is a wasteful number, since it uses less digits than its factorization.
13341103035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243775.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 13341103035 its reverse (53030114331), we get a palindrome (66371217366).
The spelling of 13341103035 in words is "thirteen billion, three hundred forty-one million, one hundred three thousand, thirty-five".
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