Base | Representation |
---|---|
bin | 1100001000100011111000… |
… | …1001100011011111001100 |
3 | 1202020101222221102000210200 |
4 | 3002020332021203133030 |
5 | 3222040300021112140 |
6 | 44212511234533500 |
7 | 2544604435250541 |
oct | 302107611433714 |
9 | 52211887360720 |
10 | 13341211113420 |
11 | 4283a80961513 |
12 | 15b5748737290 |
13 | 75a0bc752328 |
14 | 341a0a518bc8 |
15 | 18207ed11030 |
hex | c223e2637cc |
13341211113420 has 144 divisors (see below), whose sum is σ = 41921386171392. Its totient is φ = 3430727084160.
The previous prime is 13341211113413. The next prime is 13341211113437. The reversal of 13341211113420 is 2431111214331.
13341211113420 is a `hidden beast` number, since 1 + 3 + 3 + 4 + 121 + 1 + 113 + 420 = 666.
It is a super-2 number, since 2×133412111134202 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2645062 + ... + 5803341.
Almost surely, 213341211113420 is an apocalyptic number.
13341211113420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13341211113420 is an abundant number, since it is smaller than the sum of its proper divisors (28580175057972).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13341211113420 is a wasteful number, since it uses less digits than its factorization.
13341211113420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8448732 (or 8448727 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 13341211113420 its reverse (2431111214331), we get a palindrome (15772322327751).
The spelling of 13341211113420 in words is "thirteen trillion, three hundred forty-one billion, two hundred eleven million, one hundred thirteen thousand, four hundred twenty".
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