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13341244311305 = 57137580969891
BaseRepresentation
bin1100001000100100000000…
…1000001100011100001001
31202020102002020212122201222
43002021000020030130021
53222040332020430210
644212514422251425
72544605320365431
oct302110010143411
952212066778658
1013341244311305
114283a98676589
1215b5757886b75
1375a0c65a6a51
14341a10abb2c1
15182082bbc655
hexc224020c709

13341244311305 has 8 divisors (see below), whose sum is σ = 16234978993344. Its totient is φ = 10522671569200.

The previous prime is 13341244311271. The next prime is 13341244311377. The reversal of 13341244311305 is 50311344214331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13341244311305 - 228 = 13340975875849 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18790484591 + ... + 18790485300.

It is an arithmetic number, because the mean of its divisors is an integer number (2029372374168).

Almost surely, 213341244311305 is an apocalyptic number.

It is an amenable number.

13341244311305 is a deficient number, since it is larger than the sum of its proper divisors (2893734682039).

13341244311305 is an equidigital number, since it uses as much as digits as its factorization.

13341244311305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37580969967.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 13341244311305 its reverse (50311344214331), we get a palindrome (63652588525636).

The spelling of 13341244311305 in words is "thirteen trillion, three hundred forty-one billion, two hundred forty-four million, three hundred eleven thousand, three hundred five".

Divisors: 1 5 71 355 37580969891 187904849455 2668248862261 13341244311305