Base | Representation |
---|---|
bin | 1100001000100100000000… |
… | …1000001100011100001001 |
3 | 1202020102002020212122201222 |
4 | 3002021000020030130021 |
5 | 3222040332020430210 |
6 | 44212514422251425 |
7 | 2544605320365431 |
oct | 302110010143411 |
9 | 52212066778658 |
10 | 13341244311305 |
11 | 4283a98676589 |
12 | 15b5757886b75 |
13 | 75a0c65a6a51 |
14 | 341a10abb2c1 |
15 | 182082bbc655 |
hex | c224020c709 |
13341244311305 has 8 divisors (see below), whose sum is σ = 16234978993344. Its totient is φ = 10522671569200.
The previous prime is 13341244311271. The next prime is 13341244311377. The reversal of 13341244311305 is 50311344214331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13341244311305 - 228 = 13340975875849 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18790484591 + ... + 18790485300.
It is an arithmetic number, because the mean of its divisors is an integer number (2029372374168).
Almost surely, 213341244311305 is an apocalyptic number.
It is an amenable number.
13341244311305 is a deficient number, since it is larger than the sum of its proper divisors (2893734682039).
13341244311305 is an equidigital number, since it uses as much as digits as its factorization.
13341244311305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37580969967.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 13341244311305 its reverse (50311344214331), we get a palindrome (63652588525636).
The spelling of 13341244311305 in words is "thirteen trillion, three hundred forty-one billion, two hundred forty-four million, three hundred eleven thousand, three hundred five".
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