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13341300323 = 131026253871
BaseRepresentation
bin11000110110011010…
…00001011001100011
31021102210000021111012
430123031001121203
5204310333102243
610043502211135
7651416116211
oct143315013143
937383007435
1013341300323
1157268a843a
122703b83aab
131348000160
14907c0dcb1
155313bcd18
hex31b341663

13341300323 has 4 divisors (see below), whose sum is σ = 14367554208. Its totient is φ = 12315046440.

The previous prime is 13341300311. The next prime is 13341300353. The reversal of 13341300323 is 32300314331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13341300323 - 28 = 13341300067 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13341300353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513126923 + ... + 513126948.

It is an arithmetic number, because the mean of its divisors is an integer number (3591888552).

Almost surely, 213341300323 is an apocalyptic number.

13341300323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13341300323 is a deficient number, since it is larger than the sum of its proper divisors (1026253885).

13341300323 is a wasteful number, since it uses less digits than its factorization.

13341300323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1026253884.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 13341300323 its reverse (32300314331), we get a palindrome (45641614654).

The spelling of 13341300323 in words is "thirteen billion, three hundred forty-one million, three hundred thousand, three hundred twenty-three".

Divisors: 1 13 1026253871 13341300323