13341441403411 has 4 divisors (see below), whose sum is σ = 14554299712824. Its totient is φ = 12128583094000.

The previous prime is 13341441403403. The next prime is 13341441403441. The reversal of 13341441403411 is 11430414414331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13341441403411 - 2³ = 13341441403403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13341441403441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606429154690 + ... + 606429154711.

It is an arithmetic number, because the mean of its divisors is an integer number (3638574928206).

Almost surely, 2^{13341441403411} is an apocalyptic number.

13341441403411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13341441403411 is a deficient number, since it is larger than the sum of its proper divisors (1212858309413).

13341441403411 is a wasteful number, since it uses less digits than its factorization.

13341441403411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1212858309412.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 13341441403411 its reverse (11430414414331), we get a palindrome (24771855817742).

The spelling of 13341441403411 in words is "thirteen trillion, three hundred forty-one billion, four hundred forty-one million, four hundred three thousand, four hundred eleven".