Base | Representation |
---|---|
bin | 11110010101011011111101… |
… | …110110111111100001001111 |
3 | 122111101022020012121222121121 |
4 | 132111123331312333201033 |
5 | 114441330430444344301 |
6 | 1151425442422341411 |
7 | 40046611335056113 |
oct | 3625337566774117 |
9 | 574338205558547 |
10 | 133414533199951 |
11 | 39567870977553 |
12 | 12b6876928a867 |
13 | 5959c2363ca03 |
14 | 24d3425489743 |
15 | 106564153e3a1 |
hex | 7956fddbf84f |
133414533199951 has 2 divisors, whose sum is σ = 133414533199952. Its totient is φ = 133414533199950.
The previous prime is 133414533199901. The next prime is 133414533200071. The reversal of 133414533199951 is 159991335414331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133414533199951 - 27 = 133414533199823 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133414533199951.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133414533199901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66707266599975 + 66707266599976.
It is an arithmetic number, because the mean of its divisors is an integer number (66707266599976).
Almost surely, 2133414533199951 is an apocalyptic number.
133414533199951 is a deficient number, since it is larger than the sum of its proper divisors (1).
133414533199951 is an equidigital number, since it uses as much as digits as its factorization.
133414533199951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23619600, while the sum is 61.
The spelling of 133414533199951 in words is "one hundred thirty-three trillion, four hundred fourteen billion, five hundred thirty-three million, one hundred ninety-nine thousand, nine hundred fifty-one".
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