Base | Representation |
---|---|
bin | 1100001000100111111100… |
… | …0100100100000111101010 |
3 | 1202020111210211221200021111 |
4 | 3002021333010210013222 |
5 | 3222100012340334310 |
6 | 44213211304300534 |
7 | 2544643432346545 |
oct | 302117704440752 |
9 | 52214724850244 |
10 | 13342300324330 |
11 | 428448a77781a |
12 | 15b59b147174a |
13 | 75a2342c6223 |
14 | 341ab104985c |
15 | 1820e576528a |
hex | c227f1241ea |
13342300324330 has 32 divisors (see below), whose sum is σ = 24612420006720. Its totient is φ = 5204524913280.
The previous prime is 13342300324291. The next prime is 13342300324361. The reversal of 13342300324330 is 3342300324331.
It is a junction number, because it is equal to n+sod(n) for n = 13342300324292 and 13342300324301.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5997444 + ... + 7915423.
It is an arithmetic number, because the mean of its divisors is an integer number (769138125210).
Almost surely, 213342300324330 is an apocalyptic number.
13342300324330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13342300324330 is a deficient number, since it is larger than the sum of its proper divisors (11270119682390).
13342300324330 is a wasteful number, since it uses less digits than its factorization.
13342300324330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13915254.
The product of its (nonzero) digits is 46656, while the sum is 31.
Adding to 13342300324330 its reverse (3342300324331), we get a palindrome (16684600648661).
Subtracting from 13342300324330 its reverse (3342300324331), we obtain a palindrome (9999999999999).
The spelling of 13342300324330 in words is "thirteen trillion, three hundred forty-two billion, three hundred million, three hundred twenty-four thousand, three hundred thirty".
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