13342300324331 has 4 divisors (see below), whose sum is σ = 14555236717464. Its totient is φ = 12129363931200.

The previous prime is 13342300324291. The next prime is 13342300324361.

13342300324331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13342300324331 is a prime.

It is a super-2 number, since 2×13342300324331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13342300324361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606468196550 + ... + 606468196571.

It is an arithmetic number, because the mean of its divisors is an integer number (3638809179366).

Almost surely, 2^{13342300324331} is an apocalyptic number.

13342300324331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13342300324331 is a deficient number, since it is larger than the sum of its proper divisors (1212936393133).

13342300324331 is a wasteful number, since it uses less digits than its factorization.

13342300324331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1212936393132.

The product of its (nonzero) digits is 46656, while the sum is 32.

It can be divided in two parts, 13342300 and 324331, that added together give a palindrome (13666631).

The spelling of 13342300324331 in words is "thirteen trillion, three hundred forty-two billion, three hundred million, three hundred twenty-four thousand, three hundred thirty-one".