13342343012333 has 4 divisors (see below), whose sum is σ = 13342514056188. Its totient is φ = 13342171968480.

The previous prime is 13342343012321. The next prime is 13342343012429. The reversal of 13342343012333 is 33321034324331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2973962332324 + 10368380680009 = 1724518^2 + 3219997^2 .

It is a cyclic number.

It is not a de Polignac number, because 13342343012333 - 2²⁸ = 13342074576877 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13342343012293 and 13342343012302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13342343012303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85404866 + ... + 85560947.

It is an arithmetic number, because the mean of its divisors is an integer number (3335628514047).

Almost surely, 2^{13342343012333} is an apocalyptic number.

It is an amenable number.

13342343012333 is a deficient number, since it is larger than the sum of its proper divisors (171043855).

13342343012333 is an equidigital number, since it uses as much as digits as its factorization.

13342343012333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171043854.

The product of its (nonzero) digits is 139968, while the sum is 35.

Adding to 13342343012333 its reverse (33321034324331), we get a palindrome (46663377336664).

The spelling of 13342343012333 in words is "thirteen trillion, three hundred forty-two billion, three hundred forty-three million, twelve thousand, three hundred thirty-three".