Base | Representation |
---|---|
bin | 111110001000010110… |
… | …0001101111100101111 |
3 | 110202101112211010120221 |
4 | 1330100230031330233 |
5 | 4141223021404403 |
6 | 141143311352211 |
7 | 12432241253563 |
oct | 1742054157457 |
9 | 422345733527 |
10 | 133424013103 |
11 | 51648416927 |
12 | 21a37522667 |
13 | c7743875a4 |
14 | 665a1276a3 |
15 | 370d760dbd |
hex | 1f10b0df2f |
133424013103 has 4 divisors (see below), whose sum is σ = 141272484480. Its totient is φ = 125575541728.
The previous prime is 133424013097. The next prime is 133424013157. The reversal of 133424013103 is 301310424331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133424013103 - 25 = 133424013071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133424013803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3924235663 + ... + 3924235696.
It is an arithmetic number, because the mean of its divisors is an integer number (35318121120).
Almost surely, 2133424013103 is an apocalyptic number.
133424013103 is a deficient number, since it is larger than the sum of its proper divisors (7848471377).
133424013103 is an equidigital number, since it uses as much as digits as its factorization.
133424013103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7848471376.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 133424013103 its reverse (301310424331), we get a palindrome (434734437434).
The spelling of 133424013103 in words is "one hundred thirty-three billion, four hundred twenty-four million, thirteen thousand, one hundred three".
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