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133424013103 = 177848471359
BaseRepresentation
bin111110001000010110…
…0001101111100101111
3110202101112211010120221
41330100230031330233
54141223021404403
6141143311352211
712432241253563
oct1742054157457
9422345733527
10133424013103
1151648416927
1221a37522667
13c7743875a4
14665a1276a3
15370d760dbd
hex1f10b0df2f

133424013103 has 4 divisors (see below), whose sum is σ = 141272484480. Its totient is φ = 125575541728.

The previous prime is 133424013097. The next prime is 133424013157. The reversal of 133424013103 is 301310424331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133424013103 - 25 = 133424013071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133424013803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3924235663 + ... + 3924235696.

It is an arithmetic number, because the mean of its divisors is an integer number (35318121120).

Almost surely, 2133424013103 is an apocalyptic number.

133424013103 is a deficient number, since it is larger than the sum of its proper divisors (7848471377).

133424013103 is an equidigital number, since it uses as much as digits as its factorization.

133424013103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7848471376.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 133424013103 its reverse (301310424331), we get a palindrome (434734437434).

The spelling of 133424013103 in words is "one hundred thirty-three billion, four hundred twenty-four million, thirteen thousand, one hundred three".

Divisors: 1 17 7848471359 133424013103