Base | Representation |
---|---|
bin | 11000110110100111… |
… | …00011110011100001 |
3 | 1021102220020100100220 |
4 | 30123103203303201 |
5 | 204311302422423 |
6 | 10044003033253 |
7 | 651436514532 |
oct | 143323436341 |
9 | 37386210326 |
10 | 13343014113 |
11 | 5727868aa0 |
12 | 270466b829 |
13 | 1348480230 |
14 | 908138689 |
15 | 53160a9e3 |
hex | 31b4e3ce1 |
13343014113 has 32 divisors (see below), whose sum is σ = 20921873280. Its totient is φ = 7457149440.
The previous prime is 13343014109. The next prime is 13343014117. The reversal of 13343014113 is 31141034331.
It is an interprime number because it is at equal distance from previous prime (13343014109) and next prime (13343014117).
It is not a de Polignac number, because 13343014113 - 22 = 13343014109 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13343014117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 428103 + ... + 458211.
It is an arithmetic number, because the mean of its divisors is an integer number (653808540).
Almost surely, 213343014113 is an apocalyptic number.
13343014113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13343014113 is a deficient number, since it is larger than the sum of its proper divisors (7578859167).
13343014113 is a wasteful number, since it uses less digits than its factorization.
13343014113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31169.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13343014113 its reverse (31141034331), we get a palindrome (44484048444).
The spelling of 13343014113 in words is "thirteen billion, three hundred forty-three million, fourteen thousand, one hundred thirteen".
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