Base | Representation |
---|---|
bin | 1100001000101011000100… |
… | …1011111111111100011111 |
3 | 1202020120222110002020110111 |
4 | 3002022301023333330133 |
5 | 3222103223112242421 |
6 | 44213430541550451 |
7 | 2545003322203165 |
oct | 302126113777437 |
9 | 52216873066414 |
10 | 13343141134111 |
11 | 4284881351638 |
12 | 15b5ba6b75427 |
13 | 75a3395673c9 |
14 | 341b50999235 |
15 | 18214449dee1 |
hex | c22b12fff1f |
13343141134111 has 4 divisors (see below), whose sum is σ = 13343242880224. Its totient is φ = 13343039388000.
The previous prime is 13343141134097. The next prime is 13343141134123. The reversal of 13343141134111 is 11143114134331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13343141134111 - 29 = 13343141133599 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13343141134511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50676090 + ... + 50938711.
It is an arithmetic number, because the mean of its divisors is an integer number (3335810720056).
Almost surely, 213343141134111 is an apocalyptic number.
13343141134111 is a deficient number, since it is larger than the sum of its proper divisors (101746113).
13343141134111 is a wasteful number, since it uses less digits than its factorization.
13343141134111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101746112.
The product of its digits is 5184, while the sum is 31.
Adding to 13343141134111 its reverse (11143114134331), we get a palindrome (24486255268442).
The spelling of 13343141134111 in words is "thirteen trillion, three hundred forty-three billion, one hundred forty-one million, one hundred thirty-four thousand, one hundred eleven".
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