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133431434134 = 266715717067
BaseRepresentation
bin111110001000100100…
…0100001101110010110
3110202102001210011022221
41330101020201232112
54141231421343014
6141144134412554
712432361322335
oct1742110415626
9422361704287
10133431434134
1151651625409
1221a39b0115a
13c775a8532b
14665b0d9d1c
15370e229b24
hex1f11221b96

133431434134 has 4 divisors (see below), whose sum is σ = 200147151204. Its totient is φ = 66715717066.

The previous prime is 133431434119. The next prime is 133431434161. The reversal of 133431434134 is 431434134331.

133431434134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 133431434134.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33357858532 + ... + 33357858535.

It is an arithmetic number, because the mean of its divisors is an integer number (50036787801).

Almost surely, 2133431434134 is an apocalyptic number.

133431434134 is a deficient number, since it is larger than the sum of its proper divisors (66715717070).

133431434134 is an equidigital number, since it uses as much as digits as its factorization.

133431434134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66715717069.

The product of its digits is 62208, while the sum is 34.

Adding to 133431434134 its reverse (431434134331), we get a palindrome (564865568465).

The spelling of 133431434134 in words is "one hundred thirty-three billion, four hundred thirty-one million, four hundred thirty-four thousand, one hundred thirty-four".

Divisors: 1 2 66715717067 133431434134