133432041130130 has 32 divisors (see below), whose sum is σ = 258474719617200. Its totient is φ = 49409743288320.

The previous prime is 133432041130109. The next prime is 133432041130133. The reversal of 133432041130130 is 31031140234331.

It can be written as a sum of positive squares in 8 ways, for example, as 6219741711481 + 127212299418649 = 2493941^2 + 11278843^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 133432041130093 and 133432041130102.

It is not an unprimeable number, because it can be changed into a prime (133432041130133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6433549955 + ... + 6433570694.

Almost surely, 2^{133432041130130} is an apocalyptic number.

133432041130130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133432041130130 is a deficient number, since it is larger than the sum of its proper divisors (125042678487070).

133432041130130 is a wasteful number, since it uses less digits than its factorization.

133432041130130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12867120734.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 133432041130130 its reverse (31031140234331), we get a palindrome (164463181364461).

The spelling of 133432041130130 in words is "one hundred thirty-three trillion, four hundred thirty-two billion, forty-one million, one hundred thirty thousand, one hundred thirty".