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133434113 = 174776379
BaseRepresentation
bin1111111010000…
…00101100000001
3100022002011012012
413331000230001
5233124342423
621123542305
73210112511
oct775005401
9308064165
10133434113
116935802a
123882a995
132184b8c7
1413a15841
15baab078
hex7f40b01

133434113 has 4 divisors (see below), whose sum is σ = 133512240. Its totient is φ = 133355988.

The previous prime is 133434101. The next prime is 133434121. The reversal of 133434113 is 311434331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311434331 = 1323956487.

It is a cyclic number.

It is not a de Polignac number, because 133434113 - 28 = 133433857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133434163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36443 + ... + 39936.

It is an arithmetic number, because the mean of its divisors is an integer number (33378060).

Almost surely, 2133434113 is an apocalyptic number.

It is an amenable number.

133434113 is a deficient number, since it is larger than the sum of its proper divisors (78127).

133434113 is an equidigital number, since it uses as much as digits as its factorization.

133434113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78126.

The product of its digits is 1296, while the sum is 23.

The square root of 133434113 is about 11551.3684470715. The cubic root of 133434113 is about 511.0016365285.

Adding to 133434113 its reverse (311434331), we get a palindrome (444868444).

The spelling of 133434113 in words is "one hundred thirty-three million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 1747 76379 133434113